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Finding the position of a found regex #253197 30/05/15 09:03 AM
A Aotik
Aotik A	Hi, So basically I have a function here to check for this regex (searching for image links). Code: if ($regex($1-, /(https?:\/\/.*\.(?:png\|jpg))/i)) { var %s = link_ $+ $ticks $+ $rand(1,1000000) if ($sock(%s)) { sockclose %s } sockopen %s hkbot.io 80 sockmark %s $nick $chan $1 } On this line Code: sockmark %s $nick $chan $1 I want to have the link URL found so that it would be Code: sockmark %s $nick $chan %linkfound If anyone could give some insight on how this would be possible, that would be awesome. Thanks Last edited by Aotik; 30/05/15 10:52 AM.

Re: Finding the position of a found regex #253199 30/05/15 11:43 AM
Joined: Jan 2004 Posts: 1,330 L Loki12583 Hoopy frood
Loki12583 Hoopy frood L Joined: Jan 2004 Posts: 1,330	Are you looking for $regml(1)?

Re: Finding the position of a found regex Loki12583 #253202 30/05/15 11:47 AM
A Aotik
Aotik A	Will that return "http://i.imgur.com/FY1AbSo.gif" for example in the phrase "Here is a link http://i.imgur.com/FY1AbSo.gif" ? Ill try it out soon

Re: Finding the position of a found regex #253203 30/05/15 12:29 PM
A Aotik
Aotik A	Works beautifully, thanks mate!

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