Forums Scripts & Popups easier way instead of using a loop?

staff users on the server have prefixes '^ next to their names

but higher owners have a ' prefix

is there a way i can get the total users for each one without using a loop?

$nick($chan,0,') is no good as this would work for both staff and higher owners. this is for a nicklist dialog im working on.

Use regular expressions:

Above code will match the staff prefix ^ only.

If you are talking about a single command that will give you all the users in a channel/server with ^ at the beginning of their nickname, a loop is likely the only (reliable) way to get that result. The actual way you perform the loop and comparisons is up to you, but the simplest comparison would be something like this:

if (^* iswm $nick) ;command

or

if ($left($nick,1) == ^) ;command

-genius_at_work

Is ^ a mode prefix (so that "staff users" have two modes, ' and ^)? If so, you can simply use $nick()'s 4th parameter to exclude the ^ mode (/help $nick).

I have a feeling that pouncer's residing network is Buzzen. I have seen their chat netowrk with staff usermode prefixed with ^' in front. I actually tried if $nick(#,$nick,^) or based on your saying, $nick(#,0,',^)...and with .pnick alike; But they didn't work for some reason. The only one works is the regex one I posted above.