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\d in regex #191078 02/12/07 01:28 AM
Joined: Oct 2005 Posts: 827 P pouncer OP Hoopy frood
OP pouncer Hoopy frood P Joined: Oct 2005 Posts: 827	\d{4} does that mean a 4 digit number? if so, how can i make it so it can be a 1/2 digit number

Re: \d in regex pouncer #191079 02/12/07 01:41 AM
Joined: Sep 2005 Posts: 2,881 H hixxy Hoopy frood
hixxy Hoopy frood H Joined: Sep 2005 Posts: 2,881	\d{1,2} Or: \d\d?

Re: \d in regex hixxy #191080 02/12/07 01:48 AM
Joined: Oct 2005 Posts: 827 P pouncer OP Hoopy frood
OP pouncer Hoopy frood P Joined: Oct 2005 Posts: 827	thanks hixxy. i have another problem with a code you gave me a while back Code: alias test { var %str = Tom Jones if ($regex(%str, /([A-Z][a-z]{2}) (?1)/)) { echo -a pass! } } i only want it to echo pass if the 2 words in the string are length 3 (and both words start with a caps letter), why does it echo 'pass' in the above case? Last edited by pouncer; 02/12/07 01:49 AM.

Re: \d in regex pouncer #191081 02/12/07 01:56 AM
Joined: Sep 2005 Posts: 2,881 H hixxy Hoopy frood
hixxy Hoopy frood H Joined: Sep 2005 Posts: 2,881	By default a regex matches anywhere in the string, so /b/ would still match "abc", because "b" is in the string. To make an exact match you have to use the ^ and $ symbols: /^b$/ will only match "b", nothing more nothing less. So to apply that to your expression you'd use: Code: /^([A-Z][a-z]{2}) (?1)$/

Re: \d in regex hixxy #191082 02/12/07 02:00 AM
Joined: Oct 2005 Posts: 827 P pouncer OP Hoopy frood
OP pouncer Hoopy frood P Joined: Oct 2005 Posts: 827	thanks alot hixxy

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