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Joined: Apr 2006
Posts: 464
Fjord artisan
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OP
Fjord artisan
Joined: Apr 2006
Posts: 464 |
Hi,
I'm looking for an Regex instruction that can find the following pattern in a string:
00:00:00
- The 0 represents a digit from 0 to 9
- The two : signs will always be there
- Pattern will be present multiple (2) times in the same string
- Pattern will be surrounded by spaces or by horizontal tabs
- The string will contain all kinds of characters, the pattern however ALWAYS be the numbers seperated with the 2 colons.
- Only 1 of the 2 digits will always be there, the second is optional.
So it should match patterns like:
0:0:00
0:00:00
00:00:00
00:00:0
00:0:0
Op top of that, this pattern will always be present twice. So, I actually need 2 Regex instructions.
One to find the first instance, and one for the second.
I hope the query itself is clear.
If anyone knows how this can be done, please let me know!
Thanks a lot in advance.
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Joined: Jan 2007
Posts: 259
Fjord artisan
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Fjord artisan
Joined: Jan 2007
Posts: 259 |
/^(.*)([0-9][0-9]?):([0-9][0-9]?):([0-9][0-9]?)(.*)([0-9][0-9]?):([0-9][0-9]?):([0-9][0-9]?)(.*)$/
Should work for you, $regml(1) being before the first match, $regml(2-4) being the results in the first xx:xx:xx (excluding the : :), $regml(5) being the inbetween, $regml(6-8) being the next xx:xx:xx match, and $regml(9) being the rest after the last match untill the end. Example:
; %s must be the string.
if ($regex(%s,/^(.*)([0-9][0-9]?):([0-9][0-9]?):([0-9][0-9]?)(.*)([0-9][0-9]?):([0-9][0-9]?):([0-9][0-9]?)(.*)$/)) {
var %m.1 = $regml(1), %m.2 = $regml(2),%m.3 = $regml(3), %m.4 = $regml(4),%,.1 = $regml(5), %m62 = $regml(6),%m.7 = $regml(7), %m.8 = $regml(8),%m.9 = $regml(9), %m.2-4 = $+(%m.2,:,%m.3,:,%m.4), %m.6-8 = $+(%m.6,:,%m.7,:,%m.8)
}
; You can now use %m.(num) to retrive a result, 1 being before, etc as described above. I also made %m.2-4 and %m.6-8 to the whole first, and whole second.
Last edited by Kardafol; 13/01/07 12:05 AM.
Those who can, cannot. Those who cannot, can.
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Joined: Apr 2006
Posts: 464
Fjord artisan
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OP
Fjord artisan
Joined: Apr 2006
Posts: 464 |
Wow dude, thats pretty amazing. I tested it a bit, and its almost working. Bit of a re-write of your code (for me to understand):
on *:TEXT:*:#channel:{
var %string = $1-
if ($regex(%string,/^(.*)([0-9][0-9]?):([0-9][0-9]?):([0-9][0-9]?)(.*)([0-9][0-9]?):([0-9][0-9]?):([0-9][0-9]?)(.*)$/)) {
var %m.1 = $regml(1)
var %m.2 = $regml(2)
var %m.3 = $regml(3)
var %m.4 = $regml(4)
var %m.5 = $regml(5)
var %m.6 = $regml(6)
var %m.7 = $regml(7)
var %m.8 = $regml(8)
var %m.9 = $regml(9)
var %m.2-4 = $+(%m.2,:,%m.3,:,%m.4)
var %m.6-8 = $+(%m.6,:,%m.7,:,%m.8)
msg $chan 1st set is %m.2-4
msg $chan 2nd set is %m.6-8
}
}
At the moment, the problem is that it won't recognise a double digit for the first part of the pattern, so the %m.2 and %m.6 part I guess? 00:00:00 returns 0:00:00 and should return 00:00:00 00:0:0 returns 0:0:0 and should return 00:0:0 00:00:0 returns 0:00:0 and should return 00:00:0 Any idea's on how to fix this?? Thanks for helping man, really appreciated.
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Joined: Apr 2006
Posts: 464
Fjord artisan
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OP
Fjord artisan
Joined: Apr 2006
Posts: 464 |
if ($regex(%string,/^(.*) \s([0-9][0-9]?):([0-9][0-9]?):([0-9][0-9]?)(.*) \s([0-9][0-9]?):([0-9][0-9]?):([0-9][0-9]?)(.*)$/)) { I think that \s switch did it. Is that correct? Or should it be done on some other way? Thank you again 
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Joined: Jan 2007
Posts: 259
Fjord artisan
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Fjord artisan
Joined: Jan 2007
Posts: 259 |
That would break the regex. I'm thinking of a solution. (bla bla <TAB>00 <-- would not be recognized)
I can come to your IRC network, since it could speed up things.
Last edited by Kardafol; 13/01/07 01:49 AM.
Those who can, cannot. Those who cannot, can.
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Joined: Jan 2007
Posts: 259
Fjord artisan
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Fjord artisan
Joined: Jan 2007
Posts: 259 |
...
if ($regex(%string,/^(.*)([0-9][0-9]?+):([0-9][0-9]?):([0-9][0-9]?)(.*)([0-9][0-9]?+):([0-9][0-9]?):([0-9][0-9]?)(.*)$/)) {
That should do it. the + after the ? means its "Greedy", meaning it will try to fill that spot first. The regex alone:
/^(.*)([0-9][0-9]?+):([0-9][0-9]?):([0-9][0-9]?)(.*)([0-9][0-9]?+):([0-9][0-9]?):([0-9][0-9]?)(.*)$/
Last edited by Kardafol; 13/01/07 01:52 AM.
Those who can, cannot. Those who cannot, can.
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Joined: Apr 2006
Posts: 464
Fjord artisan
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OP
Fjord artisan
Joined: Apr 2006
Posts: 464 |
Nope, didn't work.
I'll send ya a pm.
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Joined: Apr 2006
Posts: 464
Fjord artisan
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OP
Fjord artisan
Joined: Apr 2006
Posts: 464 |
Sorted  Thx a lot Kardafol
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Joined: Oct 2005
Posts: 1,741
Hoopy frood
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Hoopy frood
Joined: Oct 2005
Posts: 1,741 |
Try this:
alias retest1 {
var %s = beginning text 00:0:00 middle text 00:00:00 end text
if ($regex(re1,%s,/^((?:.+\s+)?)((\d\d?):(?3):(?3))\s+((?:.+\s+)?)((?2))((?:\s+.+)?)$/i)) {
echo -a (Before): $regml(re1,1)
echo -a (Match1): $regml(re1,2)
echo -a (Middle): $regml(re1,4)
echo -a (Match2): $regml(re1,5)
echo -a (Ending): $regml(re1,6)
}
else { echo -a No Match }
}
The $regml's are shown in the code above. Note that $regml #3 is used to contain an expression that is repeated, so it doesn't contain any useful data. I wasn't sure whether you wanted to match 2 different or identical strings (strings, not patterns). The code above matches 2 different strings in 2 places with the same pattern. Example: "TEXT 00:0:00 TEXT 00:0:00 TEXT" = match Example: "TEXT 0:00:0 TEXT 00:0:00 TEXT" = match If you want to match the same string in 2 places, change the (?2) to (\2) in the code above. Example: "TEXT 00:0:00 TEXT 00:0:00 TEXT" = match Example: "TEXT 0:00:0 TEXT 00:0:00 TEXT" = NO match-genius_at_work
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Joined: Oct 2006
Posts: 166
Vogon poet
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Vogon poet
Joined: Oct 2006
Posts: 166 |
Just a note that you can group your nn:nn:nn at make length match for it. as I did below.
alias retest1 {
var %s = beginning text 00:0:00 middle text 00:00:00 end text
if ($regex(re1,%s,/(?:((\d\d?)((?1)|\:|\s|){3})|([a-z].*?)(?=\s0|$))/gi)) {
echo -a (Before): $regml(re1,1)
echo -a (Match1): $regml(re1,2)
echo -a (Middle): $regml(re1,5)
echo -a (Match2): $regml(re1,6)
echo -a (Ending): $regml(re1,9)
}
else { echo -a No Match }
}
/(?: ((\d\d?)((?1)|\:|\s|){3})|([a-z].*?)(?=\s0|$))/gi
Kind Regards, blink
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Joined: Oct 2005
Posts: 1,741
Hoopy frood
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Hoopy frood
Joined: Oct 2005
Posts: 1,741 |
Sorry, but your code doesn't work as expected. At least, not how you have it written.
alias retest2 {
var %s = $1-
if ($regex(re1,%s,/(?:((\d\d?)((?1)|\:|\s|){3})|([a-z].*?)(?=\s0|$))/gi)) {
echo -a (Before): $len($regml(re1,1)) $regml(re1,1)
echo -a (Match1): $len($regml(re1,2)) $regml(re1,2)
echo -a (Middle): $len($regml(re1,5)) $regml(re1,5)
echo -a (Match2): $len($regml(re1,6)) $regml(re1,6)
echo -a (Ending): $len($regml(re1,9)) $regml(re1,9)
}
else { echo -a No Match }
}
Works: /retest2 beginning text 00:0:00 middle text 00:00:00 end text Works: /retest2 beginning text 00:0:00 middle text 00:00:00 Fails: /retest2 beginning text 00:0:00 00:00:00 end text Fails: /retest2 00:0:00 middle text 00:00:00 end text Fails: /retest2 00:0:00 00:00:00 Fails: /retest2 beginning text 00:0:00 middle text end text Fails: /retest2 beginning text middle text end text Fails: /retest2 beginning text 000:0:00 middle text 00:00:00 end text Fails: /retest2 beginning text 00:0:000 middle text 00:00:00 end text (Note: "fails" means the results aren't what the OP requested, or can use reliably.) Since the match is this: <optional text> <pattern> <optional text> <pattern> <optional text> I tried using another group to repeat the [<optional text> <pattern>] part, but the $regml values weren't populated properly. -genius_at_work
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Joined: Oct 2006
Posts: 166
Vogon poet
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Vogon poet
Joined: Oct 2006
Posts: 166 |
That can be done easily but I thought to shorten the pattern.
Kind Regards, blink
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Joined: Jan 2007
Posts: 259
Fjord artisan
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Fjord artisan
Joined: Jan 2007
Posts: 259 |
It dosen't really matter, as we have already resolved the problem.
Those who can, cannot. Those who cannot, can.
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