Forums Scripts & Popups Non-greedy regular expression not working

Hi I have this regular expression:

//echo -a $regex(aa bb cc dd wujdkrufj%hufhuiref ee ff gg,/\s(.*?%.*?)\s/) | //echo -a $regml(1)

When executed it returns:
1
bb cc dd wujdkrufj%hufhuiref

The second .*? seems to be non-greedy as requested but the first one doesn't. Am I missing something?

I think it's vaguely explained here.

I believe what is happening is that it finds a space (\s), then repeats the '.' as few times as it can before finding a '%'. Which isn't the same as it finding the fewest characters to the left of the % before encountering a space (which is what you are expecting, I believe).

I guess one alternative that does what (I think) you want is:

or

Great, thanks for that Sais, you did understand what I was trying to do with my regular expression and your solution works as expected.

it is non greedy it starts at the first space and goes all the way to the first % which is what
\s.*?%

means

try

//echo -a $regex(aa aa%aa aa%asd sd,/(\S+?%\S+)/g) $regml(1) $regml(2)

EDIT: Seems i opened the reply window longer ago then i thought :P