Forums Scripts & Popups $regsub troubles

I'll post it here first to see if I overlook something before deciding wether it's a bug or a 'missing feature'...


//var %r = blah, %x = $regsub(%r,(a),\13,%r) | echo -s result: %r

Does anyone know a way to have it return bla3h instead of blh?
More general: how to put a number immediately after a backreference in the substitution field?

Don't cheat by saying $regsub(%r,a,a3,%r) or the like, the given regex is an example

//var %r = blah, %x = $regsub(%r,(a),\1_3,%r) | echo -s result: $remove(%r,_)
result: bla3h

The problem is that \13 is treated as a single number, the 13th capture (which is null in this case), so you're replacing the (a) with a null. The addition of a non-numeric character prior to the insertion solves that, and you can then remove it immediately prior to using it. If the text you're adding is non-numeric to begin with, it works fine.

//var %r = blah, %x = $regsub(%r,(a),\1#,%r) | echo -s result: %r
result: bla#h