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/untokenize #108992 24/01/05 06:06 PM
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nalAAlan Offline OP
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$1-: hel. lo my dog is eat. ing a cat!
/untokenize 46 $1-
$1: hel lo
$5: eat ing

Basicly instead of seperating tokens, it combins them.

Re: /untokenize #108993 24/01/05 06:41 PM
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DaveC Offline
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Quote:
$1-: hel. lo my dog is eat. ing a cat!
/untokenize 46 $1-
$1: hel lo
$5: eat ing

Basicly instead of seperating tokens, it combins them.


That doesnt make sence to me, your saying if it encounters a token seperator at the end of a $x join it to the next one?

Well assumuing you have spaces as your standard $x seperators you could do.

/tokinize 255 $replacex($1-,. $+ $chr(32),$chr(32),$chr(32),$chr(255))

Re: /untokenize #108994 24/01/05 08:23 PM
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nalAAlan Offline OP
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Yes thats what I'm saying, it will put together two tokens, and what about strings that have $chr(255) in them?

$1-: cmd "c:\program files\mirc" $chan
/untokenize $asc(") $1-
$1: cmd
$2: c:\program files\mirc
$3: $chan

Re: /untokenize #108995 24/01/05 11:05 PM
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Quote:
$1-: cmd "c:\program files\mirc" $chan
/untokenize $asc(") $1-
$1: cmd
$2: c:\program files\mirc
$3: $chan


Based on your previous example, that would actually leave you with:
$1: cmd c:\program
$2: files\mirc $chan

Anyway, the problem with your idea of this command is that it either somehow 'knows' what the current tokens are meant to be or otherwise only works by treating spaces as the delimiting token.
ie.
/tokenize 44 cow,pig sheep,.duck
/untokenize 46 $1-

When evaluated it would become /untokenize 46 cow pig sheep .duck and so would result in $1 = cow, $2 = pig, and $3 = sheep duck, which is almost certainly not what the scripter would be expecting (or hoping) to happen.

Re: /untokenize #108996 24/01/05 11:44 PM
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DaveC Offline
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Quote:
Yes thats what I'm saying, it will put together two tokens, and what about strings that have $chr(255) in them?


Umm use something else, like $chr(13), but yes i know what your getting at.

Quote:
$1-: cmd "c:\program files\mirc" $chan
/untokenize $asc(") $1-
$1: cmd
$2: c:\program files\mirc
$3: $chan


From this Im getting the impression your having trouble passing parameters becuase some of them have spaces, there is a easy trick to getting around this.
say you have this
Code:
alias blah {
  echo -a The Instruction is $1
  echo -a The Folder is $2
  echo -a The Channel is $3
}


passing it /blah cmd "c:\program files\mirc" $!chan
is going to cause problems
>The Instruction is $1cmd
>The Folder is $2 "c:\program
>The Channel is $3 files\mirc"

but you can simply do this $blah(cmd,"c:\program files\mirc",$!chan)
>The Instruction is $1cmd
>The Folder is $2 "c:\program files\mirc"
>The Channel is $3 $chan

Im not sure if that above trick/method is going to be any help to u in what you want but i hope it might be (if u want to do anything specific at all smile ).

Re: /untokenize #108997 25/01/05 12:14 AM
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nalAAlan Offline OP
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im not sure what i was talking about... must have been one of those things where i thought i had a good idea but i ddint. i think i wanted to reverse the tokenizing of a string so something like

/untokenize c[,c] text

tokenize 32 a s d f
$1: a
$2: s
$3: d
$4: f
untokenize 32 $1-
$1: a s d f

tokenize 46 a.s d.f
$1: a
$2: s d
$3: f
untokenize 46,32 $1-
$1:a.s
$2:d.f

so like it would like return it to the orginal string, then tokenize 32 the recovered string

Re: /untokenize #108998 01/02/05 06:02 PM
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argv0 Offline
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I don't know if im reading this wrong
but in the original example, you could just remove the token delimiters:

$remove(he. lo world, $chr(46))

and that will join them....... if thats what you want then just use $remove


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Re: /untokenize #108999 01/02/05 06:05 PM
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argv0 Offline
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Quote:
Yes thats what I'm saying, it will put together two tokens, and what about strings that have $chr(255) in them?

$1-: cmd "c:\program files\mirc" $chan
/untokenize $asc(") $1-
$1: cmd
$2: c:\program files\mirc
$3: $chan


Keep in mind, this example is the equivalent of
/tokenize $asc(") $1-

its also the equivalent of $remove($1-,")

I still dont see the use of this command


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