Forums Bug Reports Possible $calc Bug?

$null in $calc evaluates to zero, so $null and 0 would be equal. Saying $null in this case would not be a good indication of an error.

$calc(4 + $calc(1/0)) == $calc(4 + $null) == 4

Although this isn't much better....

$calc(4 + 1 / 0) == 0