Forums Bug Reports $int

In other programming languages, there is the Integer type, and the int() function. These are easily confused.

The general definition of the int() function, means the integer part of N. It is, in fact, the greatest integer which is not greater than N.

Examples such as $int(-2.4) proves mIRC incorrect. This should infact be -3.

Usually, the int() provided in mIRC would be denoted fix().

Here follows a substitute for $int:

alias _int {
var %int = $int($$1)
return $iif(%int > $1,$calc(%int - 1),%int)
}

According to your definition, yes. According to mIRC, no. There's no obligation for mIRC to conform to your definition, or any definition at all for that matter, so this is not a bug.

Anyway, instead of your scripted $_int you can just use $floor.

See also this lengthy discussion about the issue.

Ah, sorry for my ignorance

But I would like to point out that it is not my definition, rather a *general* one.

The common method for converting to integers is to simply remove the floating-point aspect of a number, that is, to round the number towards zero. This is the way that integer casting and conversion works in all computer languages I've used.

Edit: Too late. Damn slow typing...