Forums Scripts & Popups Evaluation problem

I tried using /hadd -m table $date($did(41))
and got an entry like Wed Jan 17 2007

So I tried /hadd -m table $($date($did(41)),0)
Which gave me $date($did(41))

I want to store in a hash table an entry like $date(ddd mmm dd yyyy)
The format for the date is stored in a dialog edit box.

Basically it looks to me like I need to evaluate the information from the dialog ID, then stick the $date around it, and store that using $(,0)

However, when I tried that, I got exactly the same thing as in my original try (as shown at the top of this post)

Try:

$date($did(41),ddd mmm dd yyyy)

Don't forget that you need an item name. Right now, your item name will be the first item (in this case, ddd).

The dialog ID 41 contains the format for the date per the users preference. Why do I need an item name? I'm using the $date function, which returns the current date in the format specified.

Using $date($did(41),ddd mmm dd yyyy) returns Wed Dec 31 1969, since $did(41) contains ddd mmm dd yyyy

Can you give an example of exactly what the dialog text box contains, and exactly what you want the hash table to contain after all commands are done. Example:

Dialog contains: aabbccdd
Hash should contain: 11223344

-genius_at_work

Dialog contains: ddd mmm dd yyyy
Hash item should return: $date(ddd mmm dd yyyy)

Ok, you should be able to do it like this:

/hadd table item $+($,date,$chr(40),$did(41),$chr(41))

-genius_at_work

Exactly. Item names cannot have spaces and you must have one.