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writing $chr #167459 24/12/06 11:38 PM
Joined: Dec 2002 Posts: 79 Richmon bc Canada F Fantas OP Babel fish
OP Fantas Babel fish F Joined: Dec 2002 Posts: 79 Richmon bc Canada	what i'm trying to do is have it echo $2 == life $3 == is $4 == good but i get life is good == on :TEXT:!word:#: { echo -a $2- $+ $chr(61) $+ $chr(61) }

Re: writing $chr Fantas #167469 25/12/06 03:56 AM
Joined: Oct 2004 Posts: 8,330 MA, USA Riamus2 Hoopy frood
Riamus2 Hoopy frood Joined: Oct 2004 Posts: 8,330 MA, USA	If you want to put == between each word, use: echo -a $replace($2-,$chr(32),$+($chr(32),==,$chr(32))) Invision Support #Invision on irc.irchighway.net

Re: writing $chr Riamus2 #167481 25/12/06 05:00 AM
Joined: Dec 2002 Posts: 79 Richmon bc Canada F Fantas OP Babel fish
OP Fantas Babel fish F Joined: Dec 2002 Posts: 79 Richmon bc Canada	thats close what i'm trying to do is find a shorter code for this $chr(36) $+ $chr(50) $chr(61) $+ $chr(61) $2 $chr(36) $+ $chr(51) $chr(61) $+ $chr(61) so i don't have to put $2 $3 $4 etc

Re: writing $chr Fantas #167500 25/12/06 11:43 AM
Joined: Oct 2003 Posts: 313 UK S Sais Fjord artisan
Sais Fjord artisan S Joined: Oct 2003 Posts: 313 UK	Something like: Code: var %i = 1, %output while (%i <= $0) { %output = %output $ $+ %i = $($+($,%i),2) inc %i } return %output ? [edit] And, by the way, there was no need to write either $ or the numerals as $chr() sequences. You could have either: Code: $ $+ 2 or Code: $!2 [/edit] Last edited by Sais; 25/12/06 11:51 AM. Sais

Re: writing $chr Fantas #167502 25/12/06 02:17 PM
Joined: Oct 2004 Posts: 8,330 MA, USA Riamus2 Hoopy frood
Riamus2 Hoopy frood Joined: Oct 2004 Posts: 8,330 MA, USA	What I gave you will insert == between all of the words. The only $N that you use is $2-. Invision Support #Invision on irc.irchighway.net

Re: writing $chr Sais #167529 25/12/06 10:44 PM
Joined: Dec 2002 Posts: 79 Richmon bc Canada F Fantas OP Babel fish
OP Fantas Babel fish F Joined: Dec 2002 Posts: 79 Richmon bc Canada	Thanks guys that got it

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