Forums Developers $did(dname,id).type ?

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Re: $did(dname,id).type ? #6605 15/01/03 02:03 AM
Joined: Dec 2002 Posts: 3,015 London, UK C Collective Hoopy frood
Collective Hoopy frood C Joined: Dec 2002 Posts: 3,015 London, UK	What for? You can tell what type of control it is because you set the ID of a control when you add it to a dialog, and $did returns the ID associated with an on DIALOG event...it would just be a different way of getting the same info, IMO adding new features and repairing old bugs is more important than adding a different way of doing something that can already be done..

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