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$chan(#chan)'s return value (any version/v6.35)
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Re: $chan(#chan)'s return value (any version/v6.35)
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221935
01/06/10
07:34 AM
Joined:
Jan 2003
Posts: 1,057
D
Doqnach
Hoopy frood
Doqnach
Hoopy frood
D
Joined:
Jan 2003
Posts: 1,057
but what order would it use? because there is the 'alphabetic order' aswell as the 'joined order'.
should it be consistant over the two by choosing just one? and which one would that be? the currently active sorting method or always alphabetic?
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$chan(#chan)'s return value (any version/v6.35)
Anonymous
31/05/10
09:35 PM
Re: $chan(#chan)'s return value (any version/v6.35)
argv0
31/05/10
09:41 PM
Re: $chan(#chan)'s return value (any version/v6.35)
Anonymous
31/05/10
09:45 PM
Re: $chan(#chan)'s return value (any version/v6.35)
argv0
31/05/10
09:52 PM
Re: $chan(#chan)'s return value (any version/v6.35)
Anonymous
31/05/10
10:04 PM
Re: $chan(#chan)'s return value (any version/v6.35)
Doqnach
01/06/10
07:34 AM
Re: $chan(#chan)'s return value (any version/v6.35)
Anonymous
01/06/10
08:09 AM
Re: $chan(#chan)'s return value (any version/v6.35)
argv0
01/06/10
04:33 PM
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