another quite obvious bug, i'm not sure if you realize this but $var() allows wildcards to be used to find variable names. so if you have at least 1 variable set, $var(%*) will be non 0 even though there isn't one named "%*"
of course this can be worked around but then there's the /var issue hixxy mentioned which is currently unsolvable (theres no way to completely alias /set) which, to me, is a huge price to pay for running this script. nice try though ;P
