bah you have the same problems i was having with dcc sends using sockets (i asked for a script, no one had one
).
ok i dont know how much you know so ill try and break it down, I am leaving some things but there not to relevent here, this might be too simple if so im sorry.
A number is not normally stored as text which it is in mirc, normally its stored as 4 bytes of data, if you had the value 45, it would be stored under x86 cpu as 45,0,0,0 if the value was 255 its 255,0,0,0 since 255 is the highest value a byte can hold if we want to store 256 we end up with this 0,1,0,0 its like an abucus the second number represents x256, 3rd x65536 (becuase this is 256x256) and 4th x16777216 (becuase this is 256x256x256), so if we wanted to store 1000000 its 64,66,15,0 (64 + 66x256 + 15x65536 + 0x16777216).
OK hopefully that sorts out how numbers are stored under x86, well NETWORK BYTE ORDER is simply the other way around the 1000000 would be stored 0,15,66,64 (0x16777216 + 15x65536 + 66x256 + 64)
now what i did in my calculation....
"%file.bytesent / 16777216" this gets the value for the 1st of the 4 numbers but it might have a decimal place to i shave it off using $int
"%file.bytesent / 65536" this gets the value for the 2nd of the 4 numbers how ever it has the 1st value x 256 also in it so i have to get ride of that, i do that by using the "% 256" which might be better known as MOD ( divide by 256 and take the remainder as your answer ) but it might have a decimal place to i shave it off using $int
"%file.bytesent / 256" this gets the value of the 3rd of the 4 numbers again however it has the 1st number x256x256 and the 2nd number x 256 also in it, again got to get ride of them so again just use "% 256" and all the others come off. but it might have a decimal place to i shave it off using $int
"%file.bytesent % 256" this gets the value of the 4th number since its the least amount we just remove all the others from it by using "% 256"
I include this following set of calculations to show it not using the % method that does confuse some people.
num1 = int(%file.bytesent / 16777216)
num2 = int((%file.bytesent - (num1 * 16777216)) / 65536)
num3 = int((%file.bytesent - (num1 * 16777216) - (num2 * 65536)) / 256)
num4 = %file.bytesent - (num1 * 16777216) - (num2 * 65536) - (num3 * 256)
As u see the calcualtion is more intensive but easier to under stand
Hope this helped. If you dont have anymore sucsess tell me ill try again, see if i can get anywhere, i hate working of specs, because u often find there is some small point missed out
