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I have a bot in my channel. Chatters can type in the command !drink, and the bot sends a list of available drinks to them via private message. The problem is that if more than one chatter types the command in at the same time, the bot floods out. I need a way to sort of hold the commands in a que or something until it's done sending to one person...then send it to the next one that had typed in the command. Any help would be appreciated.

For example:This will set a five second queue until it's run out before someone else is able to get the drinks via !drink command. Anyone who tries to get drinks within 5 second will be ignored. This way, your bot won't get flooded out.

I don't want the second person to be ignored. I just want the bot to not send to them until it has completed sending to the first person. It seems as if it should be an if/then command, but I just don't know how to do it. The second person should not have to retype the command.

That's not a queu thats a flood protection.

You could use the /play command, it allows you to specify both the delay per-line, and the max. number of requests-to-queue for a target / for all targets.

Example:
- /write the line(s) of text to a temporary file
- /play the file to the $nick
- /remove the temporary file

You could also create a [topic] for every drink in some bar.ini and play the respective topic for this or that drink to $nick.

Yup, I misunderstood you. Perhaps using timer is another alternative:

I suggest you read up on mIRC's built in flood protection.
Type /help flood

ziv.