$pos problem - mIRC Discussion Forums

i have a prob, if i do $pos(meis is test, is ,1) it returns 3, so mirc ignores the spaces in the string.
Is there a way to make mirc not ignore the spaces so it would show up 6?

(i use it in a script, so N is always 1)

and yes i did a search but that still answered my question... and i know " meis" isnt a word

grtz, Jo-W (sry about my bad english

)

that's the way it works
$pos(meis is test,is,1) returns 3
$pos(meis is test,is,2) returns 6

/help $pos

You could resort to using the $mid(%text,%number,4) identifier, you could increment the number until the end of the file and check for each four letters whether they equalled chr(32) $+ is $+ chr(32). If they do, you will know the %number you are on.

Or you could just use $findtok.
$findtok(this is my test,is,1,32)
If I understand what he is saying, that should do what he wants.

Joke wrote:
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that's the way it works
$pos(meis is test,is,1) returns 3
$pos(meis is test,is,2) returns 6

/help $pos

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the N is always 1 in my script...

post your script so we can understand what r u trying to make

Code:

alias NEW {
  set %is-item $$1
  set %is-value $$3-
  echo -s %is-item == %is-value
}

This is my code, now if I do /new testing blah is testing blah123
I get testing == blah testing blah123

so i tryd to make with the $pos to return the number where "is" is, then i used $left with the number from $pos.

Only then if i do "/new 324092is is testing" i get "324092"

still does not make any sense...

kk but the thing is i just wanna know how i can use a space in $cos

ow damn i ment $pos instead of $cos (already edited my post)

Code:

//echo # $pos(meis is test,$+($chr(32),is,$chr(32)),1)

..returns 5 (due to the space before "is").

Code:

//echo # $pos(meis is test,$+(is,$chr(32)),1)

..returns 6 like you want it to.. (btw, i agree, strange coding but i hope it helps you, whatever you re doing, lol

)

//echo # $pos(meis is test,$+(is,$chr(32)),1)
echoes 3 because of meis, please test code before posting it, especially when it is this easy to test.

If you just want to split the text into the part before and after 'is' use this code:

Code:

alias new {
  var %pos = $findtok($$1-,is,1,32)
  var %is-item = $gettok($1-,1- $+ $calc(%pos - 1),32)
  var %is-value = $gettok($1-,$calc(%pos + 1) $+ -,32)
  echo -s %is-item == %is-value
}

If you really want the position of the 'i' character from 'is' try this:

Code:

$calc($len($gettok($1-,1- $+ $calc($findtok($1-,is,1,32) - 1),32)) + 1)

That will return the number of characters(including the space in front of 'is') before the word 'is'.

lmao, ty

please test code before posting it, especially when it is this easy to test.
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you dont get my question, i asked because it went rong when i whas testing