this is just a small question but how do u add x number of items for a number::
example

if %g = 5 then write 100000

In your example, what do you want to write? Where?

-genius_at_work

write where and to what?

if %g == 5 { command }

$str(0,%g) ? or perhaps

i want to write a x number of zeros behind a 1 for the number of decimal places(its an identifier)

Use exponents, as in the example above.



-genius_at_work

Jaytea already gave the answer I think...

//var %g = 5, %x = 1 | echo -a $+(%x,$str(0,%g))

Returns: 100000

Take a look at: /help $str

i know $str, just forgot it lol. does anyone know why its $str and not $rep or something lol

Because you're adding a $string of characters. As far as why you don't consider it repeating the characters, I don't really know... Khaled had to pick one and he chose $str.

i knw it ment string but i dont know how that is better than $ran or something lol

What is $ran?

lol, nothing i typed that wrong i ment $rep and im just saying that it should be called that then $str

Too late to change it, so just accept it as-is. Besides, I think other languages use similar.