$scriptdir - 19/10/07 07:35 PM
Is there a way to pass on $scriptdir WITHOUT explicitly says it in an identifier?
As in, i have two script, A and B, in different folders (lets say C and D).
A contains an identifier that i want makes reference to the Scriptdir OF THE SCRIPT THAT CALLED THE COMMAND.
I would like to use that identifier in Script B without having to use $id($scriptdir,Something) and just use $id(Something)
Is it possible by any ways, or would i really need to use it in every call?
As in, i have two script, A and B, in different folders (lets say C and D).
A contains an identifier that i want makes reference to the Scriptdir OF THE SCRIPT THAT CALLED THE COMMAND.
I would like to use that identifier in Script B without having to use $id($scriptdir,Something) and just use $id(Something)
Is it possible by any ways, or would i really need to use it in every call?