if i have not understood it wrong, /bset -t &binvar 1 97
would add the value 97 to the &binvar, and not evaluate it to its ascii value.
but i have not gotten this to work:
//bset -t &binvar 1 97 | echo -a $bvar(&binvar,1,1000)
gives me "57 55" which is the ascii values of 9 and 7. is this a bug or have i just missunderstood it?