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$round() returning improperly #244103 24/01/14 05:09 AM
Joined: Dec 2002 Posts: 252 Ohio, USA T Talon OP Fjord artisan
OP Talon Fjord artisan T Joined: Dec 2002 Posts: 252 Ohio, USA	I found that while rounding negative numbers, the sign is kept no matter the result.. $round(-0.1,0) = -0

Re: $round() returning improperly Talon #244117 24/01/14 02:14 PM
Joined: Mar 2008 Posts: 93 Austria B BhaaL Babel fish
BhaaL Babel fish B Joined: Mar 2008 Posts: 93 Austria	With floating point numbers, theres a difference between +0 and -0 (which is the sign) I'd expect this to be the case here, and I wouldn't want to "fix" that. Does it break anything in particular for you?

Re: $round() returning improperly BhaaL #244123 24/01/14 10:47 PM
Joined: Dec 2002 Posts: 252 Ohio, USA T Talon OP Fjord artisan
OP Talon Fjord artisan T Joined: Dec 2002 Posts: 252 Ohio, USA	mainly something that required the length of the number, which $len() returned 2 which baffled me, then I outputted the result and found that it was -0, a simple $calc() around $rand() fixes the issue tho. Example: $calc($round(-0.1,0))

Re: $round() returning improperly Talon #244269 10/02/14 10:54 PM
Joined: Feb 2003 Posts: 2,812 Raccoon Hoopy frood
Raccoon Hoopy frood Joined: Feb 2003 Posts: 2,812	Numbers rounded to 0 decimal places are now integers, and -0 should be rounded to 0 with no sign. It breaks sorting, too, ie $sorttok or /window -s Well. At least I won lunch. Good philosophy, see good in bad, I like!

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