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$v1 behavior #195821 03/03/08 01:40 AM
Joined: Jul 2006 Posts: 4,149 France W Wims OP Hoopy frood
OP Wims Hoopy frood W Joined: Jul 2006 Posts: 4,149 France	considering this alias : Code: alias Ga { if (!$+($null,1)) { noop } echo -a $v1 if ($+($null,1) == $null) { noop } echo -a $v1 } After both /if, $v1 should be 1, but it return 0 when using the !. #mircscripting @ irc.swiftirc.net == the best mIRC help channel

Re: $v1 behavior Wims #195825 03/03/08 04:05 AM
Joined: Dec 2002 Posts: 503 Melbourne, Australia B Bekar Fjord artisan
Bekar Fjord artisan B Joined: Dec 2002 Posts: 503 Melbourne, Australia	Why? The first is negated (!). The $null means nothing when concatenated with another value (i.e. it's stripped/ignored). As $v1 is the first part of the comparison, I see no problems here. If you're wanting the $null to actually mean something, then use binary variables.

Re: $v1 behavior Wims #195826 03/03/08 05:33 AM
Joined: Oct 2003 Posts: 3,918 Montreal, QC, Canada A argv0 Hoopy frood
argv0 Hoopy frood A Joined: Oct 2003 Posts: 3,918 Montreal, QC, Canada	$+($null,1) == $null $+ 1 == 1 !1 == 0 (note this wont work literally because of mirc parsing issues, this is the case for !$(1) though) all of the above are facts, not assumptions. therefore if (!$+($null,1)) == if (0) $v1 seems to be 0 here. where's the bug? - argv[0] on EFnet #mIRC - "Life is a pointer to an integer without a cast"

Re: $v1 behavior argv0 #195836 03/03/08 03:35 PM
Joined: Jul 2006 Posts: 4,149 France W Wims OP Hoopy frood
OP Wims Hoopy frood W Joined: Jul 2006 Posts: 4,149 France	If (!$(1)) is the same as if (0) but it's because of the !, imo, in first case, $v1 is 1 and 0 in the second.It's just how i seen this, if it's normal behavior, i'll simply use "== $null" instead of the "!" #mircscripting @ irc.swiftirc.net == the best mIRC help channel

Re: $v1 behavior Wims #195837 03/03/08 03:53 PM
Joined: Feb 2006 Posts: 546 J jaytea Fjord artisan
jaytea Fjord artisan J Joined: Feb 2006 Posts: 546	i've also had cases where i would've preferred $v1 to return 1 instead of its negation, but i've come to accept it. "!$+()" is the whole parameter to the if condition, and the definition of $v1 is 'the first parameter of an if condition', so the behavior does make sense you could use == $null, but of course checking (%x == $null) isnt the same as (!%x). in cases where you absolutely need to check (!%x), but would like %x to be filled as $v1 you could use: Code: if (%x) / else { ; stuff with $v1 } or set variables, and so on "The only excuse for making a useless script is that one admires it intensely" - Oscar Wilde

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