Forums Scripts & Popups hi , i need help $did result

when i selected #chaco-corrientes , this message shows , can i get only #chaco-corrientes

0 +fs 0 0 0 n3 +fs 0 0 0 #chaco-corrientes +fs 0 0 0 +fs 0 0 0 +fs 0 0 0 #chaco-corrientes +fs 0

i use $did(2).seltext

thnx to all


i am a newbie

use $gettok($gettok($did(2).seltext,2,35),1,32)

/help token identifiers

chaco-corrientes+fs
they show me this ,any help?

Maybe matchtok (#) is sufficient?

thnx i want eliminate the +fs how can i do

thnx

One possible way would be to use token identifiers again
This is slightly more precise than a simple $remove, as tokens identifiers work "word"- (token separator-) sensitive...

use $gettok($gettok($did(2).seltext,2,35),1,43)

In your original post, it looked like there was a space between the channel name, which you want, and the +fs, which you don't.

That's what I was basing the usage of the character 32 token delimiter, rather than using 43, which is the ascii value for the + character.

thnx for everyhing

thnx bro for the help