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Joined: Jan 2004
Posts: 509
Fjord artisan
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OP
Fjord artisan
Joined: Jan 2004
Posts: 509 |
Say I have 2 variables, %LocalNicks and %GlobalNicks, and the are words separated by commas.
%GlobalNicks will have everything %LocalNicks has and more.
How do I remove everything in %LocalNicks from %GlobalNicks?
I've been suggested $deltok() and $remtok().
Well, I tried $remove().
$remove(%GlobalNicks,%LocalNicks) doesn't remove %LocalNicks.
My current attempted and failed code is:
$remove( $mid(%globalunbannick,3) , $($+($mid(%,localunbannick,3))) )
I've also tried $eval(<thing>,2).
Thanks.
-Neal.
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Joined: Dec 2002
Posts: 2,028
Hoopy frood
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Hoopy frood
Joined: Dec 2002
Posts: 2,028 |
$remtok alias remnicks {
var %i = 1
while ($gettok(%LocalNicks,%i,44) != $null) {
var %t = $v1
if ($istok(%GlobalNicks,%t,44)) {
set %GlobalNicks $remtok(%GlobalNicks,%t,1,44)
inc %i
}
}
}/set -s %GlobalNicks nick1,nick2,nick3,nick4,nick5,nick6,nick7,nick8,nick9,nick10 /set -s %LocalNicks nick1,nick2,nick4,nick5,nick7 /remnicks //echo -a %GlobalNicks
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Joined: Dec 2002
Posts: 2,028
Hoopy frood
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Hoopy frood
Joined: Dec 2002
Posts: 2,028 |
Actually you don't even need if ($istok alias remnicks {
var %i = 1
while ($gettok(%LocalNicks,%i,44) != $null) {
set %GlobalNicks $remtok(%GlobalNicks,$v1,1,44)
inc %i
}
}/set -s %GlobalNicks nick1,nick2,nick3,nick4,nick5,nick6,nick7,nick8,nick9,nick10 /set -s %LocalNicks nick1,nick2,nick4,nick5,nick7 /remnicks //echo -a %GlobalNicks
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Joined: Jan 2004
Posts: 509
Fjord artisan
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OP
Fjord artisan
Joined: Jan 2004
Posts: 509 |
var %i = 1
while ($gettok(%unbannick,%i,44) != $null) {
set %otherunban $remtok(%globalunbannick,$v1,1,44)
inc %i
}
/echo $chan %unbannick
/echo $chan %globalunbannick
/echo $chan %otherunban
%globalunbannick is still the same as %otherunban ..
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Joined: Dec 2002
Posts: 2,028
Hoopy frood
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Hoopy frood
Joined: Dec 2002
Posts: 2,028 |
It's remaining the same because you're not modifying it..
var %i = 1
while ($gettok(%unbannick,%i,44) != $null) {
set %globalunbannick $remtok(%globalunbannick,$v1,1,44)
inc %i
}
/echo $chan %unbannick
/echo $chan %globalunbannick
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Joined: Jan 2004
Posts: 509
Fjord artisan
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OP
Fjord artisan
Joined: Jan 2004
Posts: 509 |
Oh, I didn't want to change %globalunbannick. I wanted to $remove(%globalunbannick,%unbannick), so setting another variable as that is fine.
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Joined: Jan 2004
Posts: 509
Fjord artisan
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OP
Fjord artisan
Joined: Jan 2004
Posts: 509 |
Well, this works.
[July 11 2007 Wednesday 02:49:18 AM] <Neal`> //var %a = a b c d | var %b = a b c | echo -a $remove(%a,%b)
d
[July 11 2007 Wednesday 02:49:22 AM] <Neal`> D.
[July 11 2007 Wednesday 02:49:28 AM] <Neal`> That works.
[July 11 2007 Wednesday 02:49:49 AM] <myndzi> that's because the string "a b c" is in the string "a b c d"
[July 11 2007 Wednesday 02:50:00 AM] <myndzi> try //var %a = d c b a | var %b = a b c | echo -a $remove(%a, %b)
d c b a
So now $remove() won't work because of the order for my particular case. I need to simple bring out the evaluation of the %variables and treat them as plain text in the $remove(), no?
Anyone got any clues on what to do?
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Joined: Dec 2002
Posts: 2,028
Hoopy frood
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Hoopy frood
Joined: Dec 2002
Posts: 2,028 |
I'll be damned if I can get it to work. I tried it with a custom identifier and it didn't work. alias testing return a,b,c //var -s %a = a b c d | echo -a $remove(%a,$testing) I also tried it using /tokenize and still nothing. //var -s %a = a b c d | tokenize 32 a,b,c | echo -a $remove(%a,$1) And with the varables, still nothing. //var -s %a = d c b a | var -s %b = a,b,c | echo -a $remove(%a,%b) I would think all three of these methods should work, but they don't. 
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Joined: Nov 2006
Posts: 1,559
Hoopy frood
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Hoopy frood
Joined: Nov 2006
Posts: 1,559 |
alias return1 { return a,b,c }
alias test1 {
var %a = a b c d
echo -a $remove(%a, [ $return1 ] )
}
alias test2 {
var -s %a = a b c d, %b = b,d
echo -a $remove(%a, [ %b ] )
}that works... /help [ ] evaluation brackets
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Joined: Dec 2002
Posts: 2,028
Hoopy frood
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Hoopy frood
Joined: Dec 2002
Posts: 2,028 |
//var -s %a = d c b a | var -s %b = a,b,c | echo -a $remove(%a, [ %b ] ) Yeah that worked, although I tried using $eval. It's been so long since I've needed to use evaluation brackets, that I didn't even think of trying them. It seems to me that if evaluation brackets will work, then $eval should too. Well done. 
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Joined: Jan 2004
Posts: 509
Fjord artisan
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OP
Fjord artisan
Joined: Jan 2004
Posts: 509 |
Oh wow, thank you guys. Didn't thought about [ ].
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Joined: Jan 2003
Posts: 2,523
Hoopy frood
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Hoopy frood
Joined: Jan 2003
Posts: 2,523 |
Brackets are, in an important way, different from $eval. Bracket functionality is explained here in detail.
/.timerQ 1 0 echo /.timerQ 1 0 $timer(Q).com
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Joined: Dec 2002
Posts: 2,028
Hoopy frood
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Hoopy frood
Joined: Dec 2002
Posts: 2,028 |
Very interesting reading, thanks.
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