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$ial #16372 22/03/03 01:47 AM
Joined: Dec 2002 Posts: 332 Louisiana, USA C Cheech OP Fjord artisan
OP Cheech Fjord artisan C Joined: Dec 2002 Posts: 332 Louisiana, USA	if i use the following format $ial(!@19FF70D7.5CA92971.40FA16E0.IP,0) it returns 2 if there are 2 matches but how can i get it to return what the matches are ? like nick!blah@19FF70D7.5CA92971.40FA16E0.IP nick2!blah@19FF70D7.5CA92971.40FA16E0.IP thx

Re: $ial #16373 22/03/03 10:51 AM
Joined: Dec 2002 Posts: 94 K krunch Babel fish
krunch Babel fish K Joined: Dec 2002 Posts: 94	by using Code: $ial(!@19FF70D7.5CA92971.40FA16E0.IP,<n>) like Code: var %i = 1 while (%i <= $ial(!@19FF70D7.5CA92971.40FA16E0.IP,0)) { echo $ial(!@19FF70D7.5CA92971.40FA16E0.IP,%i) inc %i } Lets get dirty

Re: $ial #16374 23/03/03 02:43 AM
Joined: Dec 2002 Posts: 332 Louisiana, USA C Cheech OP Fjord artisan
OP Cheech Fjord artisan C Joined: Dec 2002 Posts: 332 Louisiana, USA	ok i think i asked the wrong question what i am trying to do is scan the $ial for this format !@ipaddress if there is a match i want to then return that info but i want to return it in the format $address($nick,5) like nick!user@ipaddress sorry for not getting it right the forst time and thx for any help

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