Forums Bug Reports $regsubex possible bug!

$regsubex treats third parm like plain text when it stored in a variable. see both examples below.

//var %a,%r = \1 | echo -a $or(,$regsub(abc,/(.)/g,%r,%a)) %a
* return abc black reversed.

//var %r = \1 | echo -a $regsubex(abc,/(.)/g,%r)
* return \1\1\1

I used \t for another script which already set, but I want to specify my own output manually this time.

This is the correct behaviour. The third parameter of $regsubex() evaluates differently so that identifiers and variables can be used in the substituted text. This is necessary so that things like $regsubex(abc,/\b([a-z])/g,$upper(\1)) works as expected.

If you want to use the value of a variable as the subtext you just need to use evaluation brackets to change the order of evaluation like so:

I never thought that could be evaluated specially when the third parameter contain escaped letters or number also when I used $() against the whole identifier. thanks might.